Search a number
-
+
51113431121 is a prime number
BaseRepresentation
bin101111100110100110…
…010001000001010001
311212221011221022222112
4233212212101001101
51314140014243441
635251534115105
73456431665424
oct574646210121
9155834838875
1051113431121
111a74a221365
129aa594ba95
134a87643bcc
14268c5679bb
1514e24d04eb
hexbe6991051

51113431121 has 2 divisors, whose sum is σ = 51113431122. Its totient is φ = 51113431120.

The previous prime is 51113431099. The next prime is 51113431169. The reversal of 51113431121 is 12113431115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 35203140625 + 15910290496 = 187625^2 + 126136^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51113431121 is a prime.

It is a super-2 number, since 2×511134311212 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (51113431181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25556715560 + 25556715561.

It is an arithmetic number, because the mean of its divisors is an integer number (25556715561).

Almost surely, 251113431121 is an apocalyptic number.

It is an amenable number.

51113431121 is a deficient number, since it is larger than the sum of its proper divisors (1).

51113431121 is an equidigital number, since it uses as much as digits as its factorization.

51113431121 is an evil number, because the sum of its binary digits is even.

The product of its digits is 360, while the sum is 23.

Adding to 51113431121 its reverse (12113431115), we get a palindrome (63226862236).

The spelling of 51113431121 in words is "fifty-one billion, one hundred thirteen million, four hundred thirty-one thousand, one hundred twenty-one".