Base | Representation |
---|---|
bin | 101111100110100110… |
… | …010001000001001010 |
3 | 11212221011221022222021 |
4 | 233212212101001022 |
5 | 1314140014243424 |
6 | 35251534115054 |
7 | 3456431665414 |
oct | 574646210112 |
9 | 155834838867 |
10 | 51113431114 |
11 | 1a74a221359 |
12 | 9aa594ba8a |
13 | 4a87643bc5 |
14 | 268c5679b4 |
15 | 14e24d04e4 |
hex | be699104a |
51113431114 has 16 divisors (see below), whose sum is σ = 77248987200. Its totient is φ = 25363898784.
The previous prime is 51113431099. The next prime is 51113431121. The reversal of 51113431114 is 41113431115.
It is a super-2 number, since 2×511134311142 (a number of 22 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 794419 + ... + 856345.
It is an arithmetic number, because the mean of its divisors is an integer number (4828061700).
Almost surely, 251113431114 is an apocalyptic number.
51113431114 is a deficient number, since it is larger than the sum of its proper divisors (26135556086).
51113431114 is a wasteful number, since it uses less digits than its factorization.
51113431114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65037.
The product of its digits is 720, while the sum is 25.
Adding to 51113431114 its reverse (41113431115), we get a palindrome (92226862229).
Subtracting from 51113431114 its reverse (41113431115), we obtain a palindrome (9999999999).
The spelling of 51113431114 in words is "fifty-one billion, one hundred thirteen million, four hundred thirty-one thousand, one hundred fourteen".
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