511140401 has 2 divisors, whose sum is σ = 511140402. Its totient is φ = 511140400.

The previous prime is 511140397. The next prime is 511140419. The reversal of 511140401 is 104041115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 489471376 + 21669025 = 22124^2 + 4655^2 .

It is a cyclic number.

It is not a de Polignac number, because 511140401 - 2² = 511140397 is a prime.

It is a super-2 number, since 2×511140401² = 522529019068881602, which contains 22 as substring.

It is a Sophie Germain prime.

It is a Chen prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 511140401.

It is not a weakly prime, because it can be changed into another prime (511140491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255570200 + 255570201.

It is an arithmetic number, because the mean of its divisors is an integer number (255570201).

Almost surely, 2^511140401 is an apocalyptic number.

It is an amenable number.

511140401 is a deficient number, since it is larger than the sum of its proper divisors (1).

511140401 is an equidigital number, since it uses as much as digits as its factorization.

511140401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 80, while the sum is 17.

The square root of 511140401 is about 22608.4143849143. The cubic root of 511140401 is about 799.5520414007.

Adding to 511140401 its reverse (104041115), we get a palindrome (615181516).

The spelling of 511140401 in words is "five hundred eleven million, one hundred forty thousand, four hundred one".