5111413124534 has 4 divisors (see below), whose sum is σ = 7667119686804. Its totient is φ = 2555706562266.

The previous prime is 5111413124533. The next prime is 5111413124537. The reversal of 5111413124534 is 4354213141115.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×5111413124534³ (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 5111413124494 and 5111413124503.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5111413124533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1277853281132 + ... + 1277853281135.

It is an arithmetic number, because the mean of its divisors is an integer number (1916779921701).

Almost surely, 2^{5111413124534} is an apocalyptic number.

5111413124534 is a deficient number, since it is larger than the sum of its proper divisors (2555706562270).

5111413124534 is a wasteful number, since it uses less digits than its factorization.

5111413124534 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2555706562269.

The product of its digits is 28800, while the sum is 35.

Adding to 5111413124534 its reverse (4354213141115), we get a palindrome (9465626265649).

The spelling of 5111413124534 in words is "five trillion, one hundred eleven billion, four hundred thirteen million, one hundred twenty-four thousand, five hundred thirty-four".