Base | Representation |
---|---|
bin | 10111001111100111100000… |
… | …11001111000111100111011 |
3 | 20200222110112120220211212221 |
4 | 23213303300121320330323 |
5 | 23144423231400003430 |
6 | 300413302540544511 |
7 | 13523606066362516 |
oct | 1347636031707473 |
9 | 220873476824787 |
10 | 51114144141115 |
11 | 15317428908700 |
12 | 589631b552137 |
13 | 226a073937303 |
14 | c89d1b389d7d |
15 | 5d98e221757a |
hex | 2e7cf0678f3b |
51114144141115 has 24 divisors (see below), whose sum is σ = 67792464767664. Its totient is φ = 36968542142400.
The previous prime is 51114144141079. The next prime is 51114144141163.
51114144141115 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 51114144141115 - 27 = 51114144140987 is a prime.
It is a super-2 number, since 2×511141441411152 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 233277757 + ... + 233496766.
It is an arithmetic number, because the mean of its divisors is an integer number (2824686031986).
Almost surely, 251114144141115 is an apocalyptic number.
51114144141115 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
51114144141115 is a deficient number, since it is larger than the sum of its proper divisors (16678320626549).
51114144141115 is a wasteful number, since it uses less digits than its factorization.
51114144141115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 466774731 (or 466774720 counting only the distinct ones).
The product of its digits is 6400, while the sum is 34.
It can be divided in two parts, 5111414 and 4141115, that added together give a palindrome (9252529).
The spelling of 51114144141115 in words is "fifty-one trillion, one hundred fourteen billion, one hundred forty-four million, one hundred forty-one thousand, one hundred fifteen".
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