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5111661150593 is a prime number
BaseRepresentation
bin100101001100010011010…
…1111110100000110000001
3200002200002110021022000022
41022120212233310012001
51132222140223304333
614512133102303225
71035206504611214
oct112304657640601
920080073238008
105111661150593
1116a09305056a8
126a6810b87b15
132b10487877ca
1413959741b77b
158ce75596c98
hex4a626bf4181

5111661150593 has 2 divisors, whose sum is σ = 5111661150594. Its totient is φ = 5111661150592.

The previous prime is 5111661150529. The next prime is 5111661150653. The reversal of 5111661150593 is 3950511661115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4954439384449 + 157221766144 = 2225857^2 + 396512^2 .

It is a cyclic number.

It is not a de Polignac number, because 5111661150593 - 26 = 5111661150529 is a prime.

It is a super-2 number, since 2×51116611505932 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5111661153593) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555830575296 + 2555830575297.

It is an arithmetic number, because the mean of its divisors is an integer number (2555830575297).

Almost surely, 25111661150593 is an apocalyptic number.

It is an amenable number.

5111661150593 is a deficient number, since it is larger than the sum of its proper divisors (1).

5111661150593 is an equidigital number, since it uses as much as digits as its factorization.

5111661150593 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 121500, while the sum is 44.

The spelling of 5111661150593 in words is "five trillion, one hundred eleven billion, six hundred sixty-one million, one hundred fifty thousand, five hundred ninety-three".