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51120110633 is a prime number
BaseRepresentation
bin101111100110111111…
…101111110000101001
311212221122111200112212
4233212333233300221
51314143222020013
635252333214505
73456542525264
oct574677576051
9155848450485
1051120110633
111a752a73819
129aa8031435
134a88b42297
14268d3c5cdb
1514e2d9e6a8
hexbe6fefc29

51120110633 has 2 divisors, whose sum is σ = 51120110634. Its totient is φ = 51120110632.

The previous prime is 51120110549. The next prime is 51120110653. The reversal of 51120110633 is 33601102115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 45336203929 + 5783906704 = 212923^2 + 76052^2 .

It is a cyclic number.

It is not a de Polignac number, because 51120110633 - 210 = 51120109609 is a prime.

It is a super-2 number, since 2×511201106332 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 51120110599 and 51120110608.

It is not a weakly prime, because it can be changed into another prime (51120110653) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25560055316 + 25560055317.

It is an arithmetic number, because the mean of its divisors is an integer number (25560055317).

Almost surely, 251120110633 is an apocalyptic number.

It is an amenable number.

51120110633 is a deficient number, since it is larger than the sum of its proper divisors (1).

51120110633 is an equidigital number, since it uses as much as digits as its factorization.

51120110633 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 23.

Adding to 51120110633 its reverse (33601102115), we get a palindrome (84721212748).

The spelling of 51120110633 in words is "fifty-one billion, one hundred twenty million, one hundred ten thousand, six hundred thirty-three".