Base | Representation |
---|---|
bin | 10111001111110010110011… |
… | …01001100110110100100011 |
3 | 20201000001011222012001110201 |
4 | 23213321121221212310203 |
5 | 23200023134414224011 |
6 | 300420144202410031 |
7 | 13524212221421344 |
oct | 1347713151466443 |
9 | 221001158161421 |
10 | 51120204836131 |
11 | 15319a58a24562 |
12 | 5897531200917 |
13 | 226a7cb464492 |
14 | c8a3342780cb |
15 | 5d9b4933dcc1 |
hex | 2e7e59a66d23 |
51120204836131 has 2 divisors, whose sum is σ = 51120204836132. Its totient is φ = 51120204836130.
The previous prime is 51120204836083. The next prime is 51120204836167. The reversal of 51120204836131 is 13163840202115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51120204836131 - 29 = 51120204835619 is a prime.
It is a super-2 number, since 2×511202048361312 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51120204836191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25560102418065 + 25560102418066.
It is an arithmetic number, because the mean of its divisors is an integer number (25560102418066).
Almost surely, 251120204836131 is an apocalyptic number.
51120204836131 is a deficient number, since it is larger than the sum of its proper divisors (1).
51120204836131 is an equidigital number, since it uses as much as digits as its factorization.
51120204836131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34560, while the sum is 37.
The spelling of 51120204836131 in words is "fifty-one trillion, one hundred twenty billion, two hundred four million, eight hundred thirty-six thousand, one hundred thirty-one".
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