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511202425001 is a prime number
BaseRepresentation
bin1110111000001100000…
…10011111100010101001
31210212111120112212101012
413130012002133202221
531333420310100001
61030502042033305
751635033626502
oct7340602374251
91725446485335
10511202425001
11187888495184
12830a87a8835
133928ac9b418
141aa56d47ba9
15d46e35a2bb
hex770609f8a9

511202425001 has 2 divisors, whose sum is σ = 511202425002. Its totient is φ = 511202425000.

The previous prime is 511202424961. The next prime is 511202425031. The reversal of 511202425001 is 100524202115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 380317656601 + 130884768400 = 616699^2 + 361780^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-511202425001 is a prime.

It is a super-2 number, since 2×5112024250012 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (511202425031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255601212500 + 255601212501.

It is an arithmetic number, because the mean of its divisors is an integer number (255601212501).

Almost surely, 2511202425001 is an apocalyptic number.

It is an amenable number.

511202425001 is a deficient number, since it is larger than the sum of its proper divisors (1).

511202425001 is an equidigital number, since it uses as much as digits as its factorization.

511202425001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 800, while the sum is 23.

Adding to 511202425001 its reverse (100524202115), we get a palindrome (611726627116).

The spelling of 511202425001 in words is "five hundred eleven billion, two hundred two million, four hundred twenty-five thousand, one".