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5112142537 is a prime number
BaseRepresentation
bin1001100001011010…
…10001101011001001
3111012021101202012111
410300231101223021
540432202030122
62203134542321
7240453331435
oct46055215311
914167352174
105112142537
112193742397
12ba80679a1
13636164218
14366d339c5
151edc08d77
hex130b51ac9

5112142537 has 2 divisors, whose sum is σ = 5112142538. Its totient is φ = 5112142536.

The previous prime is 5112142501. The next prime is 5112142547. The reversal of 5112142537 is 7352412115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4195930176 + 916212361 = 64776^2 + 30269^2 .

It is a cyclic number.

It is not a de Polignac number, because 5112142537 - 223 = 5103753929 is a prime.

It is a super-2 number, since 2×51121425372 = 52268002637209592738, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5112142499 and 5112142508.

It is not a weakly prime, because it can be changed into another prime (5112142547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556071268 + 2556071269.

It is an arithmetic number, because the mean of its divisors is an integer number (2556071269).

Almost surely, 25112142537 is an apocalyptic number.

It is an amenable number.

5112142537 is a deficient number, since it is larger than the sum of its proper divisors (1).

5112142537 is an equidigital number, since it uses as much as digits as its factorization.

5112142537 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 8400, while the sum is 31.

The square root of 5112142537 is about 71499.2485065403. The cubic root of 5112142537 is about 1722.6656135863.

The spelling of 5112142537 in words is "five billion, one hundred twelve million, one hundred forty-two thousand, five hundred thirty-seven".