5112144143543 has 4 divisors (see below), whose sum is σ = 5112152706648. Its totient is φ = 5112135580440.

The previous prime is 5112144143497. The next prime is 5112144143627. The reversal of 5112144143543 is 3453414412115.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5112144143543 - 2¹⁸ = 5112143881399 is a prime.

It is a super-2 number, since 2×5112144143543² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5112144143497 and 5112144143506.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5112144145543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3313028 + ... + 4604393.

It is an arithmetic number, because the mean of its divisors is an integer number (1278038176662).

Almost surely, 2^{5112144143543} is an apocalyptic number.

5112144143543 is a deficient number, since it is larger than the sum of its proper divisors (8563105).

5112144143543 is an equidigital number, since it uses as much as digits as its factorization.

5112144143543 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8563104.

The product of its digits is 115200, while the sum is 38.

Adding to 5112144143543 its reverse (3453414412115), we get a palindrome (8565558555658).

The spelling of 5112144143543 in words is "five trillion, one hundred twelve billion, one hundred forty-four million, one hundred forty-three thousand, five hundred forty-three".