Base | Representation |
---|---|
bin | 1001100001011010… |
… | …11110010001111010 |
3 | 111012021111101000211 |
4 | 10300231132101322 |
5 | 40432210203140 |
6 | 2203140021334 |
7 | 240453635116 |
oct | 46055362172 |
9 | 14167441024 |
10 | 5112194170 |
11 | 2193778166 |
12 | ba809184a |
13 | 636181885 |
14 | 366d48746 |
15 | 1edc192ea |
hex | 130b5e47a |
5112194170 has 16 divisors (see below), whose sum is σ = 9450651528. Its totient is φ = 1989610560.
The previous prime is 5112194167. The next prime is 5112194179. The reversal of 5112194170 is 714912115.
It can be written as a sum of positive squares in 4 ways, for example, as 4891463721 + 220730449 = 69939^2 + 14857^2 .
It is a super-2 number, since 2×51121941702 = 52269058463563977800, which contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (5112194179) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6908001 + ... + 6908740.
Almost surely, 25112194170 is an apocalyptic number.
5112194170 is a deficient number, since it is larger than the sum of its proper divisors (4338457358).
5112194170 is a wasteful number, since it uses less digits than its factorization.
5112194170 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13816785.
The product of its (nonzero) digits is 2520, while the sum is 31.
The square root of 5112194170 is about 71499.6095793536. The cubic root of 5112194170 is about 1722.6714132482.
The spelling of 5112194170 in words is "five billion, one hundred twelve million, one hundred ninety-four thousand, one hundred seventy".
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