Search a number
-
+
51122240503 = 192690644237
BaseRepresentation
bin101111100111000111…
…110111101111110111
311212221210111220011221
4233213013313233313
51314144243144003
635252451011211
73456566605645
oct574707675767
9155853456157
1051122240503
111a754198a44
129aa8899b07
134a89409869
14268d7bc195
1514e31707bd
hexbe71f7bf7

51122240503 has 4 divisors (see below), whose sum is σ = 53812884760. Its totient is φ = 48431596248.

The previous prime is 51122240473. The next prime is 51122240509. The reversal of 51122240503 is 30504222115.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 51122240503 - 217 = 51122109431 is a prime.

It is a super-2 number, since 2×511222405032 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51122240509) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1345322100 + ... + 1345322137.

It is an arithmetic number, because the mean of its divisors is an integer number (13453221190).

Almost surely, 251122240503 is an apocalyptic number.

51122240503 is a deficient number, since it is larger than the sum of its proper divisors (2690644257).

51122240503 is a wasteful number, since it uses less digits than its factorization.

51122240503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2690644256.

The product of its (nonzero) digits is 2400, while the sum is 25.

Adding to 51122240503 its reverse (30504222115), we get a palindrome (81626462618).

The spelling of 51122240503 in words is "fifty-one billion, one hundred twenty-two million, two hundred forty thousand, five hundred three".

Divisors: 1 19 2690644237 51122240503