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511225400354131 is a prime number
BaseRepresentation
bin111010000111101001111000…
…0011000110110010101010011
32111001002200010010202200200001
41310033103300120312111103
51014001404104442313011
65011141412353110431
7212452546665554641
oct16417236030662523
92431080103680601
10511225400354131
1113898a524976991
1249406aa8258417
1318c3446b576c48
1490356272b4191
153e1822c4327c1
hex1d0f4f0636553

511225400354131 has 2 divisors, whose sum is σ = 511225400354132. Its totient is φ = 511225400354130.

The previous prime is 511225400354099. The next prime is 511225400354143. The reversal of 511225400354131 is 131453004522115.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 511225400354131 - 25 = 511225400354099 is a prime.

It is a super-2 number, since 2×5112254003541312 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (511225400357131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255612700177065 + 255612700177066.

It is an arithmetic number, because the mean of its divisors is an integer number (255612700177066).

Almost surely, 2511225400354131 is an apocalyptic number.

511225400354131 is a deficient number, since it is larger than the sum of its proper divisors (1).

511225400354131 is an equidigital number, since it uses as much as digits as its factorization.

511225400354131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72000, while the sum is 37.

Adding to 511225400354131 its reverse (131453004522115), we get a palindrome (642678404876246).

The spelling of 511225400354131 in words is "five hundred eleven trillion, two hundred twenty-five billion, four hundred million, three hundred fifty-four thousand, one hundred thirty-one".