Base | Representation |
---|---|
bin | 1001100001011011… |
… | …11100010110011011 |
3 | 111012021201121222122 |
4 | 10300231330112123 |
5 | 40432223123324 |
6 | 2203142411455 |
7 | 240454660163 |
oct | 46055742633 |
9 | 14167647878 |
10 | 5112317339 |
11 | 2193851758 |
12 | ba8130b8b |
13 | 6361c595c |
14 | 366d7b5a3 |
15 | 1edc40a5e |
hex | 130b7c59b |
5112317339 has 2 divisors, whose sum is σ = 5112317340. Its totient is φ = 5112317338.
The previous prime is 5112317317. The next prime is 5112317377. The reversal of 5112317339 is 9337132115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5112317339 - 216 = 5112251803 is a prime.
It is a super-3 number, since 3×51123173393 (a number of 30 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 5112317299 and 5112317308.
It is not a weakly prime, because it can be changed into another prime (5112317389) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556158669 + 2556158670.
It is an arithmetic number, because the mean of its divisors is an integer number (2556158670).
Almost surely, 25112317339 is an apocalyptic number.
5112317339 is a deficient number, since it is larger than the sum of its proper divisors (1).
5112317339 is an equidigital number, since it uses as much as digits as its factorization.
5112317339 is an evil number, because the sum of its binary digits is even.
The product of its digits is 17010, while the sum is 35.
The square root of 5112317339 is about 71500.4709005472. The cubic root of 5112317339 is about 1722.6852480129.
The spelling of 5112317339 in words is "five billion, one hundred twelve million, three hundred seventeen thousand, three hundred thirty-nine".
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