Base | Representation |
---|---|
bin | 100101001100101010100… |
… | …0100100100000111100011 |
3 | 200002202002121200201100111 |
4 | 1022121111010210013203 |
5 | 1132230233203421430 |
6 | 14512342144232151 |
7 | 1035234662620546 |
oct | 112312504440743 |
9 | 20082077621314 |
10 | 5112438342115 |
11 | 16a119a188145 |
12 | 6a69a930b657 |
13 | 2b11407b2b50 |
14 | 13962c72a85d |
15 | 8cebd915c2a |
hex | 4a6551241e3 |
5112438342115 has 16 divisors (see below), whose sum is σ = 6632550979488. Its totient is φ = 3760649035776.
The previous prime is 5112438342101. The next prime is 5112438342127.
It is a happy number.
5112438342115 is nontrivially palindromic in base 10.
It is a cyclic number.
It is not a de Polignac number, because 5112438342115 - 221 = 5112436244963 is a prime.
It is a super-2 number, since 2×51124383421152 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 153004497 + ... + 153037906.
It is an arithmetic number, because the mean of its divisors is an integer number (414534436218).
Almost surely, 25112438342115 is an apocalyptic number.
5112438342115 is a deficient number, since it is larger than the sum of its proper divisors (1520112637373).
5112438342115 is a wasteful number, since it uses less digits than its factorization.
5112438342115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 306042678.
The product of its digits is 115200, while the sum is 40.
The spelling of 5112438342115 in words is "five trillion, one hundred twelve billion, four hundred thirty-eight million, three hundred forty-two thousand, one hundred fifteen".
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