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5112438342101 is a prime number
BaseRepresentation
bin100101001100101010100…
…0100100100000111010101
3200002202002121200201022222
41022121111010210013111
51132230233203421401
614512342144232125
71035234662620526
oct112312504440725
920082077621288
105112438342101
1116a119a188132
126a69a930b645
132b11407b2b3c
1413962c72a84d
158cebd915c1b
hex4a6551241d5

5112438342101 has 2 divisors, whose sum is σ = 5112438342102. Its totient is φ = 5112438342100.

The previous prime is 5112438342079. The next prime is 5112438342127. The reversal of 5112438342101 is 1012438342115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5103085518001 + 9352824100 = 2259001^2 + 96710^2 .

It is a cyclic number.

It is not a de Polignac number, because 5112438342101 - 214 = 5112438325717 is a prime.

It is a super-2 number, since 2×51124383421012 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5112438342701) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556219171050 + 2556219171051.

It is an arithmetic number, because the mean of its divisors is an integer number (2556219171051).

Almost surely, 25112438342101 is an apocalyptic number.

It is an amenable number.

5112438342101 is a deficient number, since it is larger than the sum of its proper divisors (1).

5112438342101 is an equidigital number, since it uses as much as digits as its factorization.

5112438342101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23040, while the sum is 35.

The spelling of 5112438342101 in words is "five trillion, one hundred twelve billion, four hundred thirty-eight million, three hundred forty-two thousand, one hundred one".