Base | Representation |
---|---|
bin | 100101001100101011100… |
… | …0010110101111101010011 |
3 | 200002202011220222112102112 |
4 | 1022121113002311331103 |
5 | 1132230320142222311 |
6 | 14512345325535535 |
7 | 1035235544162435 |
oct | 112312702657523 |
9 | 20082156875375 |
10 | 5112471445331 |
11 | 16a1206938078 |
12 | 6a69b84145ab |
13 | 2b1147603453 |
14 | 139632ca6655 |
15 | 8cec17a428b |
hex | 4a6570b5f53 |
5112471445331 has 2 divisors, whose sum is σ = 5112471445332. Its totient is φ = 5112471445330.
The previous prime is 5112471445309. The next prime is 5112471445337. The reversal of 5112471445331 is 1335441742115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5112471445331 - 222 = 5112467251027 is a prime.
It is a super-2 number, since 2×51124714453312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5112471445337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556235722665 + 2556235722666.
It is an arithmetic number, because the mean of its divisors is an integer number (2556235722666).
Almost surely, 25112471445331 is an apocalyptic number.
5112471445331 is a deficient number, since it is larger than the sum of its proper divisors (1).
5112471445331 is an equidigital number, since it uses as much as digits as its factorization.
5112471445331 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 201600, while the sum is 41.
The spelling of 5112471445331 in words is "five trillion, one hundred twelve billion, four hundred seventy-one million, four hundred forty-five thousand, three hundred thirty-one".
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