Base | Representation |
---|---|
bin | 1100001100000… |
… | …1101010101011 |
3 | 10120012102012002 |
4 | 3003001222223 |
5 | 101041444112 |
6 | 5023441215 |
7 | 1160361131 |
oct | 303015253 |
9 | 116172162 |
10 | 51124907 |
11 | 26949999 |
12 | 1515620b |
13 | a790432 |
14 | 6b0b751 |
15 | 474d1c2 |
hex | 30c1aab |
51124907 has 2 divisors, whose sum is σ = 51124908. Its totient is φ = 51124906.
The previous prime is 51124903. The next prime is 51124919. The reversal of 51124907 is 70942115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51124907 - 22 = 51124903 is a prime.
It is a super-2 number, since 2×511249072 = 5227512231517298, which contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 51124907.
It is not a weakly prime, because it can be changed into another prime (51124901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25562453 + 25562454.
It is an arithmetic number, because the mean of its divisors is an integer number (25562454).
Almost surely, 251124907 is an apocalyptic number.
51124907 is a deficient number, since it is larger than the sum of its proper divisors (1).
51124907 is an equidigital number, since it uses as much as digits as its factorization.
51124907 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2520, while the sum is 29.
The square root of 51124907 is about 7150.1683196971. The cubic root of 51124907 is about 371.1454809749.
The spelling of 51124907 in words is "fifty-one million, one hundred twenty-four thousand, nine hundred seven".
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