Base | Representation |
---|---|
bin | 1001100001011101… |
… | …01011101001011011 |
3 | 111012022002110201202 |
4 | 10300232223221123 |
5 | 40432300323232 |
6 | 2203150504415 |
7 | 240456425036 |
oct | 46056535133 |
9 | 14168073652 |
10 | 5112511067 |
11 | 2193974264 |
12 | ba820510b |
13 | 636262ba1 |
14 | 366dcc01d |
15 | 1edc7d162 |
hex | 130baba5b |
5112511067 has 2 divisors, whose sum is σ = 5112511068. Its totient is φ = 5112511066.
The previous prime is 5112511049. The next prime is 5112511081. The reversal of 5112511067 is 7601152115.
5112511067 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5112511067 - 216 = 5112445531 is a prime.
It is a super-2 number, since 2×51125110672 = 52275538820394956978, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5112511087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556255533 + 2556255534.
It is an arithmetic number, because the mean of its divisors is an integer number (2556255534).
Almost surely, 25112511067 is an apocalyptic number.
5112511067 is a deficient number, since it is larger than the sum of its proper divisors (1).
5112511067 is an equidigital number, since it uses as much as digits as its factorization.
5112511067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2100, while the sum is 29.
The square root of 5112511067 is about 71501.8256200497. The cubic root of 5112511067 is about 1722.7070077571.
The spelling of 5112511067 in words is "five billion, one hundred twelve million, five hundred eleven thousand, sixty-seven".
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