Base | Representation |
---|---|
bin | 100101001100101101001… |
… | …0000101111110110110001 |
3 | 200002202022200112211111110 |
4 | 1022121122100233312301 |
5 | 1132230423002001001 |
6 | 14512354534503533 |
7 | 1035240101032014 |
oct | 112313220576661 |
9 | 20082280484443 |
10 | 5112525422001 |
11 | 16a1234354598 |
12 | 6a6a12504ba9 |
13 | 2b11558518ca |
14 | 13963a11737b |
15 | 8cec63b73d6 |
hex | 4a65a42fdb1 |
5112525422001 has 24 divisors (see below), whose sum is σ = 7063112224480. Its totient is φ = 3289307180544.
The previous prime is 5112525421999. The next prime is 5112525422063. The reversal of 5112525422001 is 1002245252115.
5112525422001 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5112525422001 - 21 = 5112525421999 is a prime.
It is a super-2 number, since 2×51125254220012 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 5112525422001.
It is not an unprimeable number, because it can be changed into a prime (5112525422101) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5032641 + ... + 5962593.
Almost surely, 25112525422001 is an apocalyptic number.
It is an amenable number.
5112525422001 is a deficient number, since it is larger than the sum of its proper divisors (1950586802479).
5112525422001 is a wasteful number, since it uses less digits than its factorization.
5112525422001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 932193 (or 932164 counting only the distinct ones).
The product of its (nonzero) digits is 8000, while the sum is 30.
The spelling of 5112525422001 in words is "five trillion, one hundred twelve billion, five hundred twenty-five million, four hundred twenty-two thousand, one".
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