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51130004 = 2237345473
BaseRepresentation
bin1100001100001…
…0111010010100
310120012200011212
43003002322110
5101042130004
65023520552
71160412032
oct303027224
9116180155
1051130004
1126952802
1215159158
13a792853
146b0d552
15474e96e
hex30c2e94

51130004 has 12 divisors (see below), whose sum is σ = 91896084. Its totient is φ = 24873984.

The previous prime is 51129983. The next prime is 51130021. The reversal of 51130004 is 40003115.

It can be written as a sum of positive squares in 2 ways, for example, as 44890000 + 6240004 = 6700^2 + 2498^2 .

It is a super-2 number, since 2×511300042 = 5228554618080032, which contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 172589 + ... + 172884.

It is an arithmetic number, because the mean of its divisors is an integer number (7658007).

Almost surely, 251130004 is an apocalyptic number.

It is an amenable number.

51130004 is a deficient number, since it is larger than the sum of its proper divisors (40766080).

51130004 is a wasteful number, since it uses less digits than its factorization.

51130004 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 345514 (or 345512 counting only the distinct ones).

The product of its (nonzero) digits is 60, while the sum is 14.

The square root of 51130004 is about 7150.5247359897. The cubic root of 51130004 is about 371.1578145957.

Adding to 51130004 its reverse (40003115), we get a palindrome (91133119).

The spelling of 51130004 in words is "fifty-one million, one hundred thirty thousand, four".

Divisors: 1 2 4 37 74 148 345473 690946 1381892 12782501 25565002 51130004