Search a number
-
+
5113003743 = 3463123503
BaseRepresentation
bin1001100001100001…
…00011111011011111
3111012100000111120000
410300300203323133
540432412104433
62203205225343
7240463546311
oct46060437337
914170014500
105113003743
112194180431
12ba8402253
136363a6203
143670b97b1
151edd29113
hex130c23edf

5113003743 has 10 divisors (see below), whose sum is σ = 7637943984. Its totient is φ = 3408669108.

The previous prime is 5113003741. The next prime is 5113003789. The reversal of 5113003743 is 3473003115.

It is not a de Polignac number, because 5113003743 - 21 = 5113003741 is a prime.

It is a super-2 number, since 2×51130037432 = 52285614551864020098, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5113003741) by changing a digit.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 31561671 + ... + 31561832.

Almost surely, 25113003743 is an apocalyptic number.

5113003743 is a deficient number, since it is larger than the sum of its proper divisors (2524940241).

5113003743 is an equidigital number, since it uses as much as digits as its factorization.

5113003743 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 63123515 (or 63123506 counting only the distinct ones).

The product of its (nonzero) digits is 3780, while the sum is 27.

The square root of 5113003743 is about 71505.2707357996. The cubic root of 5113003743 is about 1722.7623431963.

Adding to 5113003743 its reverse (3473003115), we get a palindrome (8586006858).

The spelling of 5113003743 in words is "five billion, one hundred thirteen million, three thousand, seven hundred forty-three".

Divisors: 1 3 9 27 81 63123503 189370509 568111527 1704334581 5113003743