Base | Representation |
---|---|
bin | 10111010000000101011111… |
… | …10100110010111001101101 |
3 | 20201001000002101010212002021 |
4 | 23220002233310302321231 |
5 | 23200204213034404430 |
6 | 300424524102430141 |
7 | 13525016011505053 |
oct | 1350025764627155 |
9 | 221030071125067 |
10 | 51130240544365 |
11 | 15323238908704 |
12 | 5899472132351 |
13 | 226b73a674b88 |
14 | c8aa070541d3 |
15 | 5da03540207a |
hex | 2e80afd32e6d |
51130240544365 has 16 divisors (see below), whose sum is σ = 62516555474688. Its totient is φ = 40130745443776.
The previous prime is 51130240544323. The next prime is 51130240544431. The reversal of 51130240544365 is 56344504203115.
It is a cyclic number.
It is not a de Polignac number, because 51130240544365 - 29 = 51130240543853 is a prime.
It is a super-2 number, since 2×511302405443652 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2386524 + ... + 10390186.
It is an arithmetic number, because the mean of its divisors is an integer number (3907284717168).
Almost surely, 251130240544365 is an apocalyptic number.
It is an amenable number.
51130240544365 is a deficient number, since it is larger than the sum of its proper divisors (11386314930323).
51130240544365 is a wasteful number, since it uses less digits than its factorization.
51130240544365 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8027828.
The product of its (nonzero) digits is 864000, while the sum is 43.
The spelling of 51130240544365 in words is "fifty-one trillion, one hundred thirty billion, two hundred forty million, five hundred forty-four thousand, three hundred sixty-five".
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