Base | Representation |
---|---|
bin | 10111010000000101100001… |
… | …01100101101101100101011 |
3 | 20201001000010101201121002221 |
4 | 23220002300230231230223 |
5 | 23200204230312444430 |
6 | 300424525344534511 |
7 | 13525016250216664 |
oct | 1350026054555453 |
9 | 221030111647087 |
10 | 51130255203115 |
11 | 1532324610aa80 |
12 | 5899477021437 |
13 | 226b7407080aa |
14 | c8aa08d8c36b |
15 | 5da03684a57a |
hex | 2e80b0b2db2b |
51130255203115 has 16 divisors (see below), whose sum is σ = 66939615822816. Its totient is φ = 37182604838400.
The previous prime is 51130255203059. The next prime is 51130255203149.
It is a happy number.
51130255203115 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 51130255203115 - 221 = 51130253105963 is a prime.
It is a super-2 number, since 2×511302552031152 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 37261326 + ... + 38609155.
It is an arithmetic number, because the mean of its divisors is an integer number (4183725988926).
Almost surely, 251130255203115 is an apocalyptic number.
51130255203115 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
51130255203115 is a deficient number, since it is larger than the sum of its proper divisors (15809360619701).
51130255203115 is a wasteful number, since it uses less digits than its factorization.
51130255203115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 75882750.
The product of its (nonzero) digits is 22500, while the sum is 34.
The spelling of 51130255203115 in words is "fifty-one trillion, one hundred thirty billion, two hundred fifty-five million, two hundred three thousand, one hundred fifteen".
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