5113043341 has 4 divisors (see below), whose sum is σ = 5843478112. Its totient is φ = 4382608572.

The previous prime is 5113043329. The next prime is 5113043371. The reversal of 5113043341 is 1433403115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1433403115 = 5 ⋅286680623.

It is a cyclic number.

It is not a de Polignac number, because 5113043341 - 2¹¹ = 5113041293 is a prime.

It is a super-2 number, since 2×5113043341² = 52286424413888884562, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5113043371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 365217375 + ... + 365217388.

It is an arithmetic number, because the mean of its divisors is an integer number (1460869528).

Almost surely, 2^5113043341 is an apocalyptic number.

It is an amenable number.

5113043341 is a deficient number, since it is larger than the sum of its proper divisors (730434771).

5113043341 is an equidigital number, since it uses as much as digits as its factorization.

5113043341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 730434770.

The product of its (nonzero) digits is 2160, while the sum is 25.

The square root of 5113043341 is about 71505.5476239431. The cubic root of 5113043341 is about 1722.7667905343.

Adding to 5113043341 its reverse (1433403115), we get a palindrome (6546446456).

The spelling of 5113043341 in words is "five billion, one hundred thirteen million, forty-three thousand, three hundred forty-one".