Search a number
-
+
51131040000000 = 211357372879
BaseRepresentation
bin10111010000000110111110…
…11110011110100000000000
320201001002011002110102001020
423220003133132132200000
523200212332220000000
6300425135301505440
713525044556663362
oct1350033736364000
9221032132412036
1051131040000000
1115323609107544
125899655a12280
13226b83719704c
14c8aa812bad32
155da0806bcba0
hex2e80df79e800

51131040000000 has 768 divisors, whose sum is σ = 175060801843200. Its totient is φ = 13261824000000.

The previous prime is 51131039999933. The next prime is 51131040000097. The reversal of 51131040000000 is 4013115.

It is a tau number, because it is divible by the number of its divisors (768).

It is a super-2 number, since 2×511310400000002 (a number of 28 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 17759998561 + ... + 17760001439.

It is an arithmetic number, because the mean of its divisors is an integer number (227943752400).

Almost surely, 251131040000000 is an apocalyptic number.

51131040000000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 51131040000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (87530400921600).

51131040000000 is an abundant number, since it is smaller than the sum of its proper divisors (123929761843200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

51131040000000 is an frugal number, since it uses more digits than its factorization.

51131040000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2976 (or 2926 counting only the distinct ones).

The product of its (nonzero) digits is 60, while the sum is 15.

Adding to 51131040000000 its reverse (4013115), we get a palindrome (51131044013115).

The spelling of 51131040000000 in words is "fifty-one trillion, one hundred thirty-one billion, forty million", and thus it is an aban number.