5113112041 has 2 divisors, whose sum is σ = 5113112042. Its totient is φ = 5113112040.

The previous prime is 5113111987. The next prime is 5113112051. The reversal of 5113112041 is 1402113115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4872738025 + 240374016 = 69805^2 + 15504^2 .

It is a cyclic number.

It is not a de Polignac number, because 5113112041 - 2¹⁷ = 5112980969 is a prime.

It is a super-2 number, since 2×5113112041² = 52287829487638371362, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5113112051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556556020 + 2556556021.

It is an arithmetic number, because the mean of its divisors is an integer number (2556556021).

Almost surely, 2^5113112041 is an apocalyptic number.

It is an amenable number.

5113112041 is a deficient number, since it is larger than the sum of its proper divisors (1).

5113112041 is an equidigital number, since it uses as much as digits as its factorization.

5113112041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 19.

The square root of 5113112041 is about 71506.0280046375. The cubic root of 5113112041 is about 1722.7745063270.

Adding to 5113112041 its reverse (1402113115), we get a palindrome (6515225156).

The spelling of 5113112041 in words is "five billion, one hundred thirteen million, one hundred twelve thousand, forty-one".