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51131404931 = 372575377159
BaseRepresentation
bin101111100111101010…
…110101001010000011
311212222102202111102012
4233213222311022003
51314204114424211
635253415243135
73460040525255
oct574752651203
9155872674365
1051131404931
111a759388352
129aab9794ab
134a8b297cb9
142690ac5cd5
1514e3d80d8b
hexbe7ab5283

51131404931 has 8 divisors (see below), whose sum is σ = 52717676640. Its totient is φ = 49555888128.

The previous prime is 51131404927. The next prime is 51131404969. The reversal of 51131404931 is 13940413115.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 51131404931 - 22 = 51131404927 is a prime.

It is a super-2 number, since 2×511314049312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51131401931) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2679071 + ... + 2698088.

It is an arithmetic number, because the mean of its divisors is an integer number (6589709580).

Almost surely, 251131404931 is an apocalyptic number.

51131404931 is a deficient number, since it is larger than the sum of its proper divisors (1586271709).

51131404931 is a wasteful number, since it uses less digits than its factorization.

51131404931 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5377453.

The product of its (nonzero) digits is 6480, while the sum is 32.

The spelling of 51131404931 in words is "fifty-one billion, one hundred thirty-one million, four hundred four thousand, nine hundred thirty-one".

Divisors: 1 37 257 9509 5377159 198954883 1381929863 51131404931