Base | Representation |
---|---|
bin | 101111100111101010… |
… | …110101001010000011 |
3 | 11212222102202111102012 |
4 | 233213222311022003 |
5 | 1314204114424211 |
6 | 35253415243135 |
7 | 3460040525255 |
oct | 574752651203 |
9 | 155872674365 |
10 | 51131404931 |
11 | 1a759388352 |
12 | 9aab9794ab |
13 | 4a8b297cb9 |
14 | 2690ac5cd5 |
15 | 14e3d80d8b |
hex | be7ab5283 |
51131404931 has 8 divisors (see below), whose sum is σ = 52717676640. Its totient is φ = 49555888128.
The previous prime is 51131404927. The next prime is 51131404969. The reversal of 51131404931 is 13940413115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 51131404931 - 22 = 51131404927 is a prime.
It is a super-2 number, since 2×511314049312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51131401931) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2679071 + ... + 2698088.
It is an arithmetic number, because the mean of its divisors is an integer number (6589709580).
Almost surely, 251131404931 is an apocalyptic number.
51131404931 is a deficient number, since it is larger than the sum of its proper divisors (1586271709).
51131404931 is a wasteful number, since it uses less digits than its factorization.
51131404931 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5377453.
The product of its (nonzero) digits is 6480, while the sum is 32.
The spelling of 51131404931 in words is "fifty-one billion, one hundred thirty-one million, four hundred four thousand, nine hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.083 sec. • engine limits •