Base | Representation |
---|---|
bin | 100101001100111111100… |
… | …0010000111011101111111 |
3 | 200002210220200101200202202 |
4 | 1022121333002013131333 |
5 | 1132233203414443201 |
6 | 14512540053342115 |
7 | 1035261301546064 |
oct | 112317702073577 |
9 | 20083820350682 |
10 | 5113142343551 |
11 | 16a152060a910 |
12 | 6a6b6503793b |
13 | 2b12235c3648 |
14 | 139698026c6b |
15 | 8d010628c6b |
hex | 4a67f08777f |
5113142343551 has 8 divisors (see below), whose sum is σ = 5578000795344. Its totient is φ = 4648288446720.
The previous prime is 5113142343521. The next prime is 5113142343557. The reversal of 5113142343551 is 1553432413115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5113142343551 - 218 = 5113142081407 is a prime.
It is a super-2 number, since 2×51131423435512 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5113142343557) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1467821 + ... + 3518633.
It is an arithmetic number, because the mean of its divisors is an integer number (697250099418).
Almost surely, 25113142343551 is an apocalyptic number.
5113142343551 is a deficient number, since it is larger than the sum of its proper divisors (464858451793).
5113142343551 is a wasteful number, since it uses less digits than its factorization.
5113142343551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2277481.
The product of its digits is 108000, while the sum is 38.
Adding to 5113142343551 its reverse (1553432413115), we get a palindrome (6666574756666).
The spelling of 5113142343551 in words is "five trillion, one hundred thirteen billion, one hundred forty-two million, three hundred forty-three thousand, five hundred fifty-one".
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