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5113142343551 = 112266572050813
BaseRepresentation
bin100101001100111111100…
…0010000111011101111111
3200002210220200101200202202
41022121333002013131333
51132233203414443201
614512540053342115
71035261301546064
oct112317702073577
920083820350682
105113142343551
1116a152060a910
126a6b6503793b
132b12235c3648
14139698026c6b
158d010628c6b
hex4a67f08777f

5113142343551 has 8 divisors (see below), whose sum is σ = 5578000795344. Its totient is φ = 4648288446720.

The previous prime is 5113142343521. The next prime is 5113142343557. The reversal of 5113142343551 is 1553432413115.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5113142343551 - 218 = 5113142081407 is a prime.

It is a super-2 number, since 2×51131423435512 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5113142343557) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1467821 + ... + 3518633.

It is an arithmetic number, because the mean of its divisors is an integer number (697250099418).

Almost surely, 25113142343551 is an apocalyptic number.

5113142343551 is a deficient number, since it is larger than the sum of its proper divisors (464858451793).

5113142343551 is a wasteful number, since it uses less digits than its factorization.

5113142343551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2277481.

The product of its digits is 108000, while the sum is 38.

Adding to 5113142343551 its reverse (1553432413115), we get a palindrome (6666574756666).

The spelling of 5113142343551 in words is "five trillion, one hundred thirteen billion, one hundred forty-two million, three hundred forty-three thousand, five hundred fifty-one".

Divisors: 1 11 226657 2050813 2493227 22558943 464831122141 5113142343551