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51132103 = 114648373
BaseRepresentation
bin1100001100001…
…1011011000111
310120012210001121
43003003123013
5101042211403
65023534411
71160421121
oct303033307
9116183047
1051132103
1126954340
121515a407
13a7937a9
146b10211
1547503bd
hex30c36c7

51132103 has 4 divisors (see below), whose sum is σ = 55780488. Its totient is φ = 46483720.

The previous prime is 51132089. The next prime is 51132127. The reversal of 51132103 is 30123115.

51132103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 51132103 - 25 = 51132071 is a prime.

It is a super-2 number, since 2×511321032 = 5228983914405218, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51132143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2324176 + ... + 2324197.

It is an arithmetic number, because the mean of its divisors is an integer number (13945122).

Almost surely, 251132103 is an apocalyptic number.

51132103 is a deficient number, since it is larger than the sum of its proper divisors (4648385).

51132103 is a wasteful number, since it uses less digits than its factorization.

51132103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4648384.

The product of its (nonzero) digits is 90, while the sum is 16.

The square root of 51132103 is about 7150.6715069286. The cubic root of 51132103 is about 371.1628934766.

Adding to 51132103 its reverse (30123115), we get a palindrome (81255218).

The spelling of 51132103 in words is "fifty-one million, one hundred thirty-two thousand, one hundred three".

Divisors: 1 11 4648373 51132103