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51132143 is a prime number
BaseRepresentation
bin1100001100001…
…1011011101111
310120012210010002
43003003123233
5101042212033
65023534515
71160421206
oct303033357
9116183102
1051132143
1126954377
121515a43b
13a79380a
146b1023d
1547503e8
hex30c36ef

51132143 has 2 divisors, whose sum is σ = 51132144. Its totient is φ = 51132142.

The previous prime is 51132139. The next prime is 51132163. The reversal of 51132143 is 34123115.

It is an a-pointer prime, because the next prime (51132163) can be obtained adding 51132143 to its sum of digits (20).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 51132143 - 22 = 51132139 is a prime.

It is a super-2 number, since 2×511321432 = 5228992095544898, which contains 22 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51132163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25566071 + 25566072.

It is an arithmetic number, because the mean of its divisors is an integer number (25566072).

Almost surely, 251132143 is an apocalyptic number.

51132143 is a deficient number, since it is larger than the sum of its proper divisors (1).

51132143 is an equidigital number, since it uses as much as digits as its factorization.

51132143 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 360, while the sum is 20.

The square root of 51132143 is about 7150.6743038681. The cubic root of 51132143 is about 371.1629902619.

Adding to 51132143 its reverse (34123115), we get a palindrome (85255258).

Subtracting from 51132143 its reverse (34123115), we obtain a triangular number (17009028 = T5832).

The spelling of 51132143 in words is "fifty-one million, one hundred thirty-two thousand, one hundred forty-three".