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5113211451 = 34736263911
BaseRepresentation
bin1001100001100010…
…10110101000111011
3111012100102001110220
410300301112220323
540432440231301
62203213511123
7240465403005
oct46061265073
914170361426
105113211451
112194302497
12ba84a24a3
1363644990a
14367131375
151edd6a936
hex130c56a3b

5113211451 has 8 divisors (see below), whose sum is σ = 6962671104. Its totient is φ = 3336279720.

The previous prime is 5113211423. The next prime is 5113211491. The reversal of 5113211451 is 1541123115.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 5113211451 - 219 = 5112687163 is a prime.

It is a super-2 number, since 2×51132114512 = 52289862685275050802, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (5113211401) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18131815 + ... + 18132096.

It is an arithmetic number, because the mean of its divisors is an integer number (870333888).

Almost surely, 25113211451 is an apocalyptic number.

5113211451 is a deficient number, since it is larger than the sum of its proper divisors (1849459653).

5113211451 is a wasteful number, since it uses less digits than its factorization.

5113211451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36263961.

The product of its digits is 600, while the sum is 24.

The square root of 5113211451 is about 71506.7231174804. The cubic root of 5113211451 is about 1722.7856710803.

Adding to 5113211451 its reverse (1541123115), we get a palindrome (6654334566).

The spelling of 5113211451 in words is "five billion, one hundred thirteen million, two hundred eleven thousand, four hundred fifty-one".

Divisors: 1 3 47 141 36263911 108791733 1704403817 5113211451