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5113214601 = 3111031150287
BaseRepresentation
bin1001100001100010…
…10111011010001001
3111012100102012210120
410300301113122021
540432440331401
62203213533453
7240465415125
oct46061273211
914170365716
105113214601
1121943048a0
12ba84a4289
1363644b191
14367132585
151edd6b836
hex130c57689

5113214601 has 16 divisors (see below), whose sum is σ = 7444666368. Its totient is φ = 3095891600.

The previous prime is 5113214599. The next prime is 5113214611. The reversal of 5113214601 is 1064123115.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 5113214601 - 21 = 5113214599 is a prime.

It is a super-2 number, since 2×51132146012 = 52289927111759178402, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (5113214611) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 41121 + ... + 109166.

It is an arithmetic number, because the mean of its divisors is an integer number (465291648).

Almost surely, 25113214601 is an apocalyptic number.

It is an amenable number.

5113214601 is a deficient number, since it is larger than the sum of its proper divisors (2331451767).

5113214601 is a wasteful number, since it uses less digits than its factorization.

5113214601 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 151332.

The product of its (nonzero) digits is 720, while the sum is 24.

The square root of 5113214601 is about 71506.7451433779. The cubic root of 5113214601 is about 1722.7860248550.

Adding to 5113214601 its reverse (1064123115), we get a palindrome (6177337716).

The spelling of 5113214601 in words is "five billion, one hundred thirteen million, two hundred fourteen thousand, six hundred one".

Divisors: 1 3 11 33 1031 3093 11341 34023 150287 450861 1653157 4959471 154945897 464837691 1704404867 5113214601