Base | Representation |
---|---|
bin | 100101001101000001110… |
… | …1011001100111010001011 |
3 | 200002211010002221100202002 |
4 | 1022122003223030322023 |
5 | 1132233333334110403 |
6 | 14512551514501215 |
7 | 1035263235526523 |
oct | 112320353147213 |
9 | 20084102840662 |
10 | 5113220222603 |
11 | 16a1560572569 |
12 | 6a6b8713480b |
13 | 2b123679051c |
14 | 1396a44da683 |
15 | 8d0173ae188 |
hex | 4a683acce8b |
5113220222603 has 2 divisors, whose sum is σ = 5113220222604. Its totient is φ = 5113220222602.
The previous prime is 5113220222519. The next prime is 5113220222633. The reversal of 5113220222603 is 3062220223115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5113220222603 - 212 = 5113220218507 is a prime.
It is a super-2 number, since 2×51132202226032 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5113220222633) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556610111301 + 2556610111302.
It is an arithmetic number, because the mean of its divisors is an integer number (2556610111302).
Almost surely, 25113220222603 is an apocalyptic number.
5113220222603 is a deficient number, since it is larger than the sum of its proper divisors (1).
5113220222603 is an equidigital number, since it uses as much as digits as its factorization.
5113220222603 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 5113220222603 its reverse (3062220223115), we get a palindrome (8175440445718).
The spelling of 5113220222603 in words is "five trillion, one hundred thirteen billion, two hundred twenty million, two hundred twenty-two thousand, six hundred three".
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