Base | Representation |
---|---|
bin | 100101001101000001110… |
… | …1111111000100101111111 |
3 | 200002211010012020201120100 |
4 | 1022122003233320211333 |
5 | 1132233334142400421 |
6 | 14512552001052143 |
7 | 1035263252131335 |
oct | 112320357704577 |
9 | 20084105221510 |
10 | 5113221450111 |
11 | 16a1561230835 |
12 | 6a6b87627053 |
13 | 2b1236b00168 |
14 | 1396a4739b55 |
15 | 8d017552c26 |
hex | 4a683bf897f |
5113221450111 has 12 divisors (see below), whose sum is σ = 7386508153960. Its totient is φ = 3408470990640.
The previous prime is 5113221450091. The next prime is 5113221450149. The reversal of 5113221450111 is 1110541223115.
5113221450111 is a `hidden beast` number, since 5 + 1 + 132 + 2 + 14 + 501 + 11 = 666.
It is not a de Polignac number, because 5113221450111 - 27 = 5113221449983 is a prime.
It is a super-2 number, since 2×51132214501112 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5113221452111) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 28514776 + ... + 28693533.
Almost surely, 25113221450111 is an apocalyptic number.
5113221450111 is a deficient number, since it is larger than the sum of its proper divisors (2273286703849).
5113221450111 is a wasteful number, since it uses less digits than its factorization.
5113221450111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 57218246 (or 57218243 counting only the distinct ones).
The product of its (nonzero) digits is 1200, while the sum is 27.
Adding to 5113221450111 its reverse (1110541223115), we get a palindrome (6223762673226).
The spelling of 5113221450111 in words is "five trillion, one hundred thirteen billion, two hundred twenty-one million, four hundred fifty thousand, one hundred eleven".
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