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5113221449983 is a prime number
BaseRepresentation
bin100101001101000001110…
…1111111000100011111111
3200002211010012020201101121
41022122003233320203333
51132233334142344413
614512552001051411
71035263252131063
oct112320357704377
920084105221347
105113221449983
1116a1561230729
126a6b87626b67
132b1236b0009a
141396a4739aa3
158d017552b8d
hex4a683bf88ff

5113221449983 has 2 divisors, whose sum is σ = 5113221449984. Its totient is φ = 5113221449982.

The previous prime is 5113221449981. The next prime is 5113221450061. The reversal of 5113221449983 is 3899441223115.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5113221449983 - 21 = 5113221449981 is a prime.

It is a super-2 number, since 2×51132214499832 (a number of 26 digits) contains 22 as substring.

Together with 5113221449981, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 5113221449983.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5113221449981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556610724991 + 2556610724992.

It is an arithmetic number, because the mean of its divisors is an integer number (2556610724992).

Almost surely, 25113221449983 is an apocalyptic number.

5113221449983 is a deficient number, since it is larger than the sum of its proper divisors (1).

5113221449983 is an equidigital number, since it uses as much as digits as its factorization.

5113221449983 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1866240, while the sum is 52.

The spelling of 5113221449983 in words is "five trillion, one hundred thirteen billion, two hundred twenty-one million, four hundred forty-nine thousand, nine hundred eighty-three".