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511323303041 is a prime number
BaseRepresentation
bin1110111000011010011…
…11100110110010000001
31210212211000000002212122
413130031033212302001
531334142231144131
61030522040534025
751641032235555
oct7341517466201
91725730002778
10511323303041
1118793a746691
1283121181315
13392aa041ba5
141aa69011865
15d479c85d7b
hex770d3e6c81

511323303041 has 2 divisors, whose sum is σ = 511323303042. Its totient is φ = 511323303040.

The previous prime is 511323303037. The next prime is 511323303059. The reversal of 511323303041 is 140303323115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 508185062641 + 3138240400 = 712871^2 + 56020^2 .

It is a cyclic number.

It is not a de Polignac number, because 511323303041 - 22 = 511323303037 is a prime.

It is a super-2 number, since 2×5113233030412 (a number of 24 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 511323303041.

It is not a weakly prime, because it can be changed into another prime (511323303031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255661651520 + 255661651521.

It is an arithmetic number, because the mean of its divisors is an integer number (255661651521).

Almost surely, 2511323303041 is an apocalyptic number.

It is an amenable number.

511323303041 is a deficient number, since it is larger than the sum of its proper divisors (1).

511323303041 is an equidigital number, since it uses as much as digits as its factorization.

511323303041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3240, while the sum is 26.

Adding to 511323303041 its reverse (140303323115), we get a palindrome (651626626156).

The spelling of 511323303041 in words is "five hundred eleven billion, three hundred twenty-three million, three hundred three thousand, forty-one".