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5113394137 is a prime number
BaseRepresentation
bin1001100001100100…
…00011001111011001
3111012100202100002001
410300302003033121
540433012103022
62203221441001
7240500063425
oct46062031731
914170670061
105113394137
112194417775
12ba8570161
136364b1b07
1436717bb85
151edda4b27
hex130c833d9

5113394137 has 2 divisors, whose sum is σ = 5113394138. Its totient is φ = 5113394136.

The previous prime is 5113394047. The next prime is 5113394161. The reversal of 5113394137 is 7314933115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4811364496 + 302029641 = 69364^2 + 17379^2 .

It is a cyclic number.

It is not a de Polignac number, because 5113394137 - 231 = 2965910489 is a prime.

It is a super-2 number, since 2×51133941372 = 52293599200611949538, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5113394096 and 5113394105.

It is not a weakly prime, because it can be changed into another prime (5113394537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556697068 + 2556697069.

It is an arithmetic number, because the mean of its divisors is an integer number (2556697069).

Almost surely, 25113394137 is an apocalyptic number.

It is an amenable number.

5113394137 is a deficient number, since it is larger than the sum of its proper divisors (1).

5113394137 is an equidigital number, since it uses as much as digits as its factorization.

5113394137 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 34020, while the sum is 37.

The square root of 5113394137 is about 71508.0005104324. Note that the first 3 decimals coincide. The cubic root of 5113394137 is about 1722.8061881975.

The spelling of 5113394137 in words is "five billion, one hundred thirteen million, three hundred ninety-four thousand, one hundred thirty-seven".