5113403 has 2 divisors, whose sum is σ = 5113404. Its totient is φ = 5113402.

The previous prime is 5113399. The next prime is 5113417. The reversal of 5113403 is 3043115.

5113403 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5113403 - 2² = 5113399 is a prime.

It is a super-2 number, since 2×5113403² = 52293780480818, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5113103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556701 + 2556702.

It is an arithmetic number, because the mean of its divisors is an integer number (2556702).

Almost surely, 2^5113403 is an apocalyptic number.

5113403 is a deficient number, since it is larger than the sum of its proper divisors (1).

5113403 is an equidigital number, since it uses as much as digits as its factorization.

5113403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 180, while the sum is 17.

The square root of 5113403 is about 2261.2834851031. The cubic root of 5113403 is about 172.2807183572.

Adding to 5113403 its reverse (3043115), we get a palindrome (8156518).

The spelling of 5113403 in words is "five million, one hundred thirteen thousand, four hundred three".