Base | Representation |
---|---|
bin | 100101001101000111011… |
… | …1111010001011010011111 |
3 | 200002211121100002202002022 |
4 | 1022122032333101122133 |
5 | 1132234230432031221 |
6 | 14513022415050355 |
7 | 1035301032065516 |
oct | 112321677213237 |
9 | 20084540082068 |
10 | 5113410033311 |
11 | 16a1648726118 |
12 | 6a701a8109bb |
13 | 2b1266bbaa58 |
14 | 1396c17c967d |
15 | 8d028da44ab |
hex | 4a68efd169f |
5113410033311 has 4 divisors (see below), whose sum is σ = 5113424435112. Its totient is φ = 5113395631512.
The previous prime is 5113410033301. The next prime is 5113410033331. The reversal of 5113410033311 is 1133300143115.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5113410033311 - 26 = 5113410033247 is a prime.
It is a super-2 number, since 2×51134100333112 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5113410033301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6654500 + ... + 7383033.
It is an arithmetic number, because the mean of its divisors is an integer number (1278356108778).
Almost surely, 25113410033311 is an apocalyptic number.
5113410033311 is a deficient number, since it is larger than the sum of its proper divisors (14401801).
5113410033311 is a wasteful number, since it uses less digits than its factorization.
5113410033311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14401800.
The product of its (nonzero) digits is 1620, while the sum is 26.
Adding to 5113410033311 its reverse (1133300143115), we get a palindrome (6246710176426).
The spelling of 5113410033311 in words is "five trillion, one hundred thirteen billion, four hundred ten million, thirty-three thousand, three hundred eleven".
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