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511343000043 = 31663465122037
BaseRepresentation
bin1110111000011100110…
…10101111100111101011
31210212212101001211002020
413130032122233213223
531334212302000133
61030524023035523
751641361533331
oct7341632574753
91725771054066
10511343000043
1118794a87a2a7
128312789bba3
13392b114a415
141aa6b89bb51
15d47b8770b3
hex770e6af9eb

511343000043 has 16 divisors (see below), whose sum is σ = 682378285056. Its totient is φ = 340601637600.

The previous prime is 511343000011. The next prime is 511343000057. The reversal of 511343000043 is 340000343115.

It is a happy number.

It is not a de Polignac number, because 511343000043 - 25 = 511343000011 is a prime.

It is a super-2 number, since 2×5113430000432 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 511342999977 and 511343000022.

It is not an unprimeable number, because it can be changed into a prime (511343000083) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23192821 + ... + 23214857.

It is an arithmetic number, because the mean of its divisors is an integer number (42648642816).

Almost surely, 2511343000043 is an apocalyptic number.

511343000043 is a deficient number, since it is larger than the sum of its proper divisors (171035285013).

511343000043 is a wasteful number, since it uses less digits than its factorization.

511343000043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28354.

The product of its (nonzero) digits is 2160, while the sum is 24.

Adding to 511343000043 its reverse (340000343115), we get a palindrome (851343343158).

The spelling of 511343000043 in words is "five hundred eleven billion, three hundred forty-three million, forty-three", and thus it is an aban number.

Divisors: 1 3 1663 4651 4989 13953 22037 66111 7734613 23203839 36647531 102494087 109942593 307482261 170447666681 511343000043