Base | Representation |
---|---|
bin | 101111100111110101… |
… | …111111110010001101 |
3 | 11212222122021012122211 |
4 | 233213311333302031 |
5 | 1314210342111140 |
6 | 35254002110421 |
7 | 3460104436156 |
oct | 574765776215 |
9 | 155878235584 |
10 | 51134332045 |
11 | 1a75aaa7555 |
12 | 9ab094b411 |
13 | 4a8ba81414 |
14 | 269124892d |
15 | 14e425d2ea |
hex | be7d7fc8d |
51134332045 has 32 divisors (see below), whose sum is σ = 65289045600. Its totient is φ = 38445933568.
The previous prime is 51134332037. The next prime is 51134332091. The reversal of 51134332045 is 54023343115.
It can be written as a sum of positive squares in 16 ways, for example, as 20142137929 + 30992194116 = 141923^2 + 176046^2 .
It is not a de Polignac number, because 51134332045 - 23 = 51134332037 is a prime.
It is a super-2 number, since 2×511343320452 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 51134331998 and 51134332016.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 27241647 + ... + 27243523.
It is an arithmetic number, because the mean of its divisors is an integer number (2040282675).
Almost surely, 251134332045 is an apocalyptic number.
It is an amenable number.
51134332045 is a deficient number, since it is larger than the sum of its proper divisors (14154713555).
51134332045 is a wasteful number, since it uses less digits than its factorization.
51134332045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3042 (or 3008 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 31.
The spelling of 51134332045 in words is "fifty-one billion, one hundred thirty-four million, three hundred thirty-two thousand, forty-five".
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