Base | Representation |
---|---|
bin | 101111100111110110… |
… | …011010001011001101 |
3 | 11212222122110200221101 |
4 | 233213312122023031 |
5 | 1314210404041031 |
6 | 35254004303101 |
7 | 3460105366261 |
oct | 574766321315 |
9 | 155878420841 |
10 | 51134440141 |
11 | 1a760070794 |
12 | 9ab09a1a91 |
13 | 4a8babb695 |
14 | 26912760a1 |
15 | 14e4280361 |
hex | be7d9a2cd |
51134440141 has 8 divisors (see below), whose sum is σ = 51335648000. Its totient is φ = 50933324880.
The previous prime is 51134440111. The next prime is 51134440183. The reversal of 51134440141 is 14104443115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 51134440141 - 25 = 51134440109 is a prime.
It is a super-2 number, since 2×511344401412 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51134440111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1212040 + ... + 1253518.
It is an arithmetic number, because the mean of its divisors is an integer number (6416956000).
Almost surely, 251134440141 is an apocalyptic number.
It is an amenable number.
51134440141 is a deficient number, since it is larger than the sum of its proper divisors (201207859).
51134440141 is a wasteful number, since it uses less digits than its factorization.
51134440141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46299.
The product of its (nonzero) digits is 3840, while the sum is 28.
Adding to 51134440141 its reverse (14104443115), we get a palindrome (65238883256).
The spelling of 51134440141 in words is "fifty-one billion, one hundred thirty-four million, four hundred forty thousand, one hundred forty-one".
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