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51134440183 is a prime number
BaseRepresentation
bin101111100111110110…
…011010001011110111
311212222122110200222221
4233213312122023313
51314210404041213
635254004303211
73460105366351
oct574766321367
9155878420887
1051134440183
111a760070822
129ab09a1b07
134a8babb6c8
1426912760d1
1514e428038d
hexbe7d9a2f7

51134440183 has 2 divisors, whose sum is σ = 51134440184. Its totient is φ = 51134440182.

The previous prime is 51134440111. The next prime is 51134440207. The reversal of 51134440183 is 38104443115.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 51134440183 - 225 = 51100885751 is a prime.

It is a super-2 number, since 2×511344401832 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51134443183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25567220091 + 25567220092.

It is an arithmetic number, because the mean of its divisors is an integer number (25567220092).

Almost surely, 251134440183 is an apocalyptic number.

51134440183 is a deficient number, since it is larger than the sum of its proper divisors (1).

51134440183 is an equidigital number, since it uses as much as digits as its factorization.

51134440183 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23040, while the sum is 34.

Adding to 51134440183 its reverse (38104443115), we get a palindrome (89238883298).

The spelling of 51134440183 in words is "fifty-one billion, one hundred thirty-four million, four hundred forty thousand, one hundred eighty-three".