Base | Representation |
---|---|
bin | 10111010000001101011100… |
… | …00000111010101110101111 |
3 | 20201001102002120201111200102 |
4 | 23220012232000322232233 |
5 | 23200241431303310043 |
6 | 300430511203421315 |
7 | 13525226464103012 |
oct | 1350065600725657 |
9 | 221042076644612 |
10 | 51134505135023 |
11 | 153250270907a2 |
12 | 589a26238483b |
13 | 226bc6a0471bb |
14 | c8accd5a1379 |
15 | 5da1d49de6b8 |
hex | 2e81ae03abaf |
51134505135023 has 4 divisors (see below), whose sum is σ = 51136700054880. Its totient is φ = 51132310215168.
The previous prime is 51134505135017. The next prime is 51134505135037. The reversal of 51134505135023 is 32053150543115.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51134505135023 is a prime.
It is a super-2 number, since 2×511345051350232 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51134505135053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1097424983 + ... + 1097471576.
It is an arithmetic number, because the mean of its divisors is an integer number (12784175013720).
Almost surely, 251134505135023 is an apocalyptic number.
51134505135023 is a deficient number, since it is larger than the sum of its proper divisors (2194919857).
51134505135023 is a wasteful number, since it uses less digits than its factorization.
51134505135023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2194919856.
The product of its (nonzero) digits is 135000, while the sum is 38.
Adding to 51134505135023 its reverse (32053150543115), we get a palindrome (83187655678138).
The spelling of 51134505135023 in words is "fifty-one trillion, one hundred thirty-four billion, five hundred five million, one hundred thirty-five thousand, twenty-three".
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