Base | Representation |
---|---|
bin | 10111010000001110011111… |
… | …00100100000010000000011 |
3 | 20201001110112211001200201221 |
4 | 23220013033210200100003 |
5 | 23200244104414040000 |
6 | 300431043114135511 |
7 | 13525246441242646 |
oct | 1350071744402003 |
9 | 221043484050657 |
10 | 51135068111875 |
11 | 15325295951620 |
12 | 589a39aa21597 |
13 | 226c02987c1b7 |
14 | c8ad4426ba5d |
15 | 5da21914761a |
hex | 2e81cf920403 |
51135068111875 has 40 divisors (see below), whose sum is σ = 69711503178240. Its totient is φ = 37186911300000.
The previous prime is 51135068111857. The next prime is 51135068111957. The reversal of 51135068111875 is 57811186053115.
It is a happy number.
It is not a de Polignac number, because 51135068111875 - 215 = 51135068079107 is a prime.
It is a super-2 number, since 2×511350681118752 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 119128890 + ... + 119557360.
It is an arithmetic number, because the mean of its divisors is an integer number (1742787579456).
Almost surely, 251135068111875 is an apocalyptic number.
51135068111875 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
51135068111875 is a deficient number, since it is larger than the sum of its proper divisors (18576435066365).
51135068111875 is a wasteful number, since it uses less digits than its factorization.
51135068111875 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 445861 (or 445846 counting only the distinct ones).
The product of its (nonzero) digits is 1008000, while the sum is 52.
The spelling of 51135068111875 in words is "fifty-one trillion, one hundred thirty-five billion, sixty-eight million, one hundred eleven thousand, eight hundred seventy-five".
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