Base | Representation |
---|---|
bin | 101111100111111010… |
… | …011110111000100001 |
3 | 11212222201110221202202 |
4 | 233213322132320201 |
5 | 1314211142224001 |
6 | 35254043222545 |
7 | 3460120434464 |
oct | 574772367041 |
9 | 155881427682 |
10 | 51135508001 |
11 | 1a760730016 |
12 | 9ab1217a55 |
13 | 4a8c0a3756 |
14 | 26914732db |
15 | 14e43e196b |
hex | be7e9ee21 |
51135508001 has 2 divisors, whose sum is σ = 51135508002. Its totient is φ = 51135508000.
The previous prime is 51135507967. The next prime is 51135508063. The reversal of 51135508001 is 10080553115.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 51110357776 + 25150225 = 226076^2 + 5015^2 .
It is a cyclic number.
It is not a de Polignac number, because 51135508001 - 222 = 51131313697 is a prime.
It is a super-2 number, since 2×511355080012 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51135508301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25567754000 + 25567754001.
It is an arithmetic number, because the mean of its divisors is an integer number (25567754001).
Almost surely, 251135508001 is an apocalyptic number.
It is an amenable number.
51135508001 is a deficient number, since it is larger than the sum of its proper divisors (1).
51135508001 is an equidigital number, since it uses as much as digits as its factorization.
51135508001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3000, while the sum is 29.
The spelling of 51135508001 in words is "fifty-one billion, one hundred thirty-five million, five hundred eight thousand, one".
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