Base | Representation |
---|---|
bin | 100101001101001110011… |
… | …0010000101000110111011 |
3 | 200002212012110120020102012 |
4 | 1022122130302011012323 |
5 | 1132240214203043214 |
6 | 14513101403200135 |
7 | 1035306542125433 |
oct | 112323462050673 |
9 | 20085173506365 |
10 | 5113641456059 |
11 | 16a1757320494 |
12 | 6a708421604b |
13 | 2b12a2b277a6 |
14 | 13970442b2c3 |
15 | 8d03e36903e |
hex | 4a69cc851bb |
5113641456059 has 2 divisors, whose sum is σ = 5113641456060. Its totient is φ = 5113641456058.
The previous prime is 5113641455987. The next prime is 5113641456151. The reversal of 5113641456059 is 9506541463115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5113641456059 - 216 = 5113641390523 is a prime.
It is a super-2 number, since 2×51136414560592 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5113641455998 and 5113641456016.
It is not a weakly prime, because it can be changed into another prime (5113641476059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556820728029 + 2556820728030.
It is an arithmetic number, because the mean of its divisors is an integer number (2556820728030).
Almost surely, 25113641456059 is an apocalyptic number.
5113641456059 is a deficient number, since it is larger than the sum of its proper divisors (1).
5113641456059 is an equidigital number, since it uses as much as digits as its factorization.
5113641456059 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944000, while the sum is 50.
The spelling of 5113641456059 in words is "five trillion, one hundred thirteen billion, six hundred forty-one million, four hundred fifty-six thousand, fifty-nine".
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