511400313343 has 4 divisors (see below), whose sum is σ = 511464640288. Its totient is φ = 511335986400.

The previous prime is 511400313337. The next prime is 511400313371. The reversal of 511400313343 is 343313004115.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 511400313343 - 2⁵ = 511400313311 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (511400313323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32151546 + ... + 32167447.

It is an arithmetic number, because the mean of its divisors is an integer number (127866160072).

Almost surely, 2^511400313343 is an apocalyptic number.

511400313343 is a deficient number, since it is larger than the sum of its proper divisors (64326945).

511400313343 is an equidigital number, since it uses as much as digits as its factorization.

511400313343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 64326944.

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 511400313343 its reverse (343313004115), we get a palindrome (854713317458).

The spelling of 511400313343 in words is "five hundred eleven billion, four hundred million, three hundred thirteen thousand, three hundred forty-three".